MCQ Quiz: Simple Harmonic Motion- Challenging Problems 16 Mar 2017 A spring of force constant k is cut into two parts whose lengths are in the ratio 1:2. The two pails are now connected in parallel and a block of mass m is suspended at the end of the combined spring. Find the period of oscillation performed by the block. 2*pi*squareroot(m/9k) 2*pi*squareroot(2m/9k) 2*pi*squareroot(m/3k) 2*pi*squareroot(4m/9k) A body is executing SHM under the action of force whose maximum magnitude is 50N. Find the magnitude of force acting on the particle at the time when its energy is half kinetic and half potential. 25*sq.root(2) 25 50 50*sq.root(2) A block is kept on a horizontal table. The table is undergoing simple harmonic motion of frequency 3Hz in a horizontal plane. The coefficient of static friction between block and the table surface is 0.72. Find the maximum amplitude of the table at which the block does not slip on the surface 1 cm 3 cm 2 cm 4 cm A simple pendulum has time period T1. When the point of suspension moves vertically up according to the equation y = kt^2 where k = 1 m/s2 and't' is time then the time period of the pendulum is T2 then (T1/T2)^2 IS 5 / 6 11 / 10 6 / 5 5 / 4 A particle is executing SHM of amplitude A about the mean position x = 0. Which of the following cannot be a possible phase difference between the positions of the particle at x = + A/2 and x = -A/root(2). 75° 165° 135° 195° Two bodies P & Q of equal mass are suspended from two separate massless springs of force constants k1 & k2 respectively. If the maximum velocity of them are equal during their motion, the ratio of amplitude of P to Q is : k1/k2 sq.root(k2/k1) k2/k1 sq.root(k1/k2) A particle performing SHM is found at its equilibrium at t = 1 sec. and it is found to have a speed of 0.25 m/s at t = 2 sec. If the period of oscillationis 6 sec. Calculate amplitude of oscillation in m 3/(2*PI) 3/(4*PI) 6/(PI) 3/(8*PI) The maximum acceleration of a particle in SHM is made two times keeping the maximum speed to be constant. It is possible when amplitude of oscillation is doubled while frequency remains constant amplitude is doubled while frequency is halved frequency is doubled while amplitude is halved frequency is doubled while amplitude remains constant A ring of diameter 2m oscillates as a compound pendulum about a horizontal axis passing through a point at its rim. It oscillates such that its centre move in a plane which is perpendicular to the plane of the ring. The equivalent length of the simple pendulum is 2 m 4 m 1.5 m 3 m A liquid of mass m is oscillating with time period T in a U-tube of area of cross-section A. If the liquid is placed in another tube of A/4 cross section area then the time period will be T 2T T / 2 none of these Share this post
